Exercise 6.A.13

Answers

Proof. From the Law of Cosines, we have

||u v||2 = ||u||2 + ||v||2 2||u||||v||cos 𝜃 ||u||2 2u,v + ||v||2 = ||u||2 + ||v||2 2||u||||v||cos 𝜃 2u,v = 2||u||||v||cos 𝜃 cos 𝜃 = u,v ||u||||v||

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2017-10-06 00:00
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