Exercise 6.A.19

Answers

Proof. We have

||u + v||2 ||u v||2 = u + v,u + vu v,u v = u,u + 2u,v + v,v (u,u 2u,v + v,v) = 4u,v

Dividing by 4 yields the desired result. □

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2017-10-06 00:00
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