Homepage › Solution manuals › Sheldon Axler › Linear Algebra Done Right › Exercise 6.B.7

Exercise 6.B.7

Answers

Proof. Defining $φ (p) = p (\frac{1}{2})$ and $⟨ p, q ⟩ = \int_{0}^{1} p (x) q (x) dx$ and using the formula from 6.43 together with the basis found in Exercise 5, we find that

q (x) = - 15 x^{2} + 15 x - \frac{3}{2} .

□

celiopassos

2017-10-06 00:00

Exercise 6.B.7

Answers

Comments

Add answer