Exercise 7.B.4

Answers

Proof. The forward direction is basically the same as 7.22 and 7.24.

Suppose all pairs of eigenvectors corresponding to distinct eigenvalues of T are orthogonal and

V = E(λ1,T) E(λm,T),

where λ1,,λm are distinct eigenvalues of T. Consider the constructed by concatenating orthonormal bases of E(λ1,T),,E(λm,T). By 5.41 (e) this list has length dim V . Moreover, because all pairs of eigenvectors corresponding to distinct eigenvalues of T are orthogonal, by 6.26 this is list is also linearly indepedent. Therefore V has an orthonormal basis consisting of eigenvectors of T and is normal by 7.24. □

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2017-10-06 00:00
Comments
  • what about the other side of the implication ??
    vedanshivaghela2025-11-05