Exercise 7.D.5

Answers

Proof. We have

M (T^{∗} T) = M (T^{∗}) M (T) = (\begin{matrix} 0 & 1 \\ - 4 & 0 \end{matrix}) (\begin{matrix} 0 & - 4 \\ 1 & 0 \end{matrix}) = (\begin{matrix} 1 & 0 \\ 0 & 16 \end{matrix}) .

Therefore, the singular values of $T$ are $1$ and $4$ . □

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2017-10-06 00:00