Exercise 8.A.6

Answers

Proof. Suppose by contradiction that S L(3) is a square root of T. Note that V = null T3. We have

V = null T3 = null R6 = null R3 = null RT null R2T = null T2,

where the third line follows by 8.4. But this a contradiction, since T2(z1,z2,z3) = (z3,0,0), we see that null T2 = {(0,0,z) : z }, then we can’t have V null T2. □

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2017-10-06 00:00
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