Exercise 8.C.15

Answers

Proof. (a) Just repeat the proof of 8.40 replacing I with v, Tj with Tjv and n2 with n.

(b) This is essentially the same as the proof of 8.46.

Let q denote the minimal polynomial of T. Then we also have q(T)v = 0. Furthermore, deg q deg p. By the Division Algorithm for Polynomials (4.8), there exist s,r (𝔽) such that

q = sp + r

and deg r < deg p. This implies that

0 = q(T)v = s(T)p(T)v = r(T)v = r(T)v.

By the same reasoning used in the proof, it follows that r = 0. □

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2017-10-06 00:00
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