Homepage › Solution manuals › Sheldon Axler › Linear Algebra Done Right › Exercise 8.C.2
Exercise 8.C.2
Answers
Proof. We have
Hence is a polynomial multiple of the characteristic polynomial. Therefore, . □
2017-10-06 00:00
Homepage › Solution manuals › Sheldon Axler › Linear Algebra Done Right › Exercise 8.C.2
Proof. We have
Hence is a polynomial multiple of the characteristic polynomial. Therefore, . □