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Exercise 8.C.4
Answers
Proof.
Let
Then
Define by
Then and the eigenvalues of are thus and (the entries on the diagonal). Now 8.36 implies that the minimal polynomial of is a polynomial multiple of . The previous work shows that and . Hence is the minimal polynomial of . By Exercise 11 in section 8B, the multiplicity of is and of is . Thereby the characteristic polynomial of is . □