Homepage › Solution manuals › Sheldon Axler › Linear Algebra Done Right › Exercise 8.C.9
Exercise 8.C.9
Answers
Proof. Since
multiplying both sides by we get
Hence is a polynomial multiple of the minimal polynomial of (by 8.46). As it turns out, this is actually the minimal polynomial of (with the coefficients multiplied by ). To see this, suppose by contradiction that it is not. Hence, the minimal polynomial of has degree at most . This means that
for some , not all equal . Multiplying both sides of the equation above by , we get
which is a contradiction, because the minimal polynomial of has degree . □