Exercise 9.A.11

Answers

Proof. From the definitions, it is easy to see that

(T

C^2 + bT_C + cI) = 0.

Therefore z2 + bz + c is polynomial multiple of the minimal polynomial of T

C(see8.46).Notethat,becausethispolynomialhasrealcoefficients,iteitherhastworealrootsortwononrealroots.ThusThasaneigenvalueifandonlyifT_Chasarealroot(see9.10),whichhappensifandonlyifz^2 + bz + chasarealroot(bythepreviousreasoningand8.49),whichhappensifandonlyifb^2 4c. □

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2017-10-06 00:00
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