Exercise 9.A.4

Answers

Proof. Suppose v1,,vm spans V . Let v V . Then v + i0 V and we can write

v+i0 = λ1v1++λmvm = (Re λ1v1++Re λmvm)+i(Im λ1v1++Im λmvm)

for some λ1,,λm . The equation above implies that

Re λ1v1 + + Re λmvm = v

Therefore v span (v1, ,vm). Hence v1,,vm spans V .

Conversely, suppose v1,,vm spans V . Then we can reduce this list to a basis of V . But a basis of V is also a basis V . Therefore we can reduce v1,,vm to a basis of V and this implies that it spans V . □

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2017-10-06 00:00
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