Exercise 1.5.1

Finish the following proof for Theorem 1.5.7. Assume B is a countable set. Thus, there exists f : N B , which is 1 1 and onto. Let A B be an infinite subset of B . We must show that A is countable.

Let n 1 = min { n N : f ( n ) A } . As a start to a definition of g : N A set g ( 1 ) = f ( n 1 ) . Show how to inductively continue this process to produce a 1-1 function g from N onto A .

Answers

Let n k = min { n N f ( n ) A , n { n 1 , n 2 , , n k 1 } } and g ( k ) = f ( n k ) . since g : N A is 1-1 and onto, A is countable.

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2022-01-27 00:00
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