Exercise 2.6.3

If ( x n ) and ( y n ) are Cauchy sequences, then one easy way to prove that ( x n + y n ) is Cauchy is to use the Cauchy Criterion. By Theorem 2.6.4, ( x n ) and ( y n ) must be convergent, and the Algebraic Limit Theorem then implies ( x n + y n ) is convergent and hence Cauchy.

(a)
Give a direct argument that ( x n + y n ) is a Cauchy sequence that does not use the Cauchy Criterion or the Algebraic Limit Theorem.
(b)
Do the same for the product ( x n y n ) .

Answers

(a)
We have | ( x n + y n ) ( x m + y m ) | | x n x m | + | y n y m | < 𝜖 2 + 𝜖 2 = 𝜖
(b)
Bound | x n | M 1 , and | y n | M 2 then | x n y n x m y m | = | ( x n y n x n y m ) + ( x n y m x m y m ) | | x n ( y n y m ) | + | y m ( x n x m ) | M 1 | y n y m | + M 2 | x n x m | < 𝜖 2 + 𝜖 2 = 𝜖

After setting | y n y m | < 𝜖 ( 2 M 1 ) and | x n x m | < 𝜖 ( 2 M 2 ) .

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2022-01-27 00:00
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