Exercise 2.7.8

Consider each of the following propositions. Provide short proofs for those that are true and counterexamples for any that are not.

(a)
If a n converges absolutely, then a n 2 also converges absolutely.
(b)
If a n converges and ( b n ) converges, then a n b n converges.
(c)
If a n converges conditionally, then n 2 a n diverges.

Answers

(a)
True since ( a n ) 0 so eventually a n 2 | a n | meaning a n 2 converges by a comparsion test with | a n | .
(b)
False, let a n = ( 1 ) n n and b n = ( 1 ) n n . a n converges by the alternating series test, but a n b n = 1 n diverges.
(c)
True, suppose ( n 2 a n ) converges, since ( n 2 a n ) 0 we have | n 2 a n | < 1 for n > N , implying | a n | < 1 n 2 . But if | a n | < 1 n 2 then a comparsion test with 1 n 2 implies a n converges absolutely, contradicting the assumption that a n converges conditionally. Therefore n 2 a n must diverge.
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2022-01-27 00:00
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