Homepage › Solution manuals › Stephen Abbott › Understanding Analysis › Exercise 3.2.9
Exercise 3.2.9
[De Morgan’s Laws] A proof for De Morgan’s Laws in the case of two sets is outlined in Exercise 1.2.5. The general argument is similar.
- (a)
- Given a collection of sets , show that
- (b)
- Now, provide the details for the proof of Theorem 3.2.14.
Answers
- (a)
-
If
then
meaning
for all
implying
for all
and so finally
. This shows
To show the reverse inclusion suppose then for all meaning and so the reverse inclusion
Is true, completing the proof.
- (b)
-
Let
, if
and
. Let
be a subsequence of
fully contained in
or
. the subsequence
must also converge to
, meaning
is in
or
, the rest is by induction.
Now let
Each is open by Theorem 3.2.13, thus Theorem 3.2.3 (ii) implies is open, and so is closed.