Exercise 4.6.3

Question

State a similar definition for the left-hand limit
  $$
  \lim _{x \rightarrow c^{-}} f(x)=L
  $$

Ulisse Mini · Accepted Answer

For all $\epsilon > 0$ there exists a $\delta > 0$ such that $0 < c-x < \delta$ implies $|f(x)-L|<\epsilon$.

Answers