Exercise 5.3.4

Let f be differentiable on an interval A containing zero, and assume ( x n ) is a sequence in A with ( x n ) 0 and x n 0 .

(a)
If f ( x n ) = 0 for all n N , show f ( 0 ) = 0 and f ( 0 ) = 0 .
(b)
Add the assumption that f is twice-differentiable at zero and show that f ′′ ( 0 ) = 0 as well.

Answers

(a)
Since f ( 0 ) exists and f ( x n ) = 0 for all n we have f ( 0 ) = lim f ( x n ) x n = 0

(b)
By the mean value theorem over [ 0 , x n ] there exists a c n ( 0 , x n ) such that f ( c n ) = f ( x n ) x n

Then like in (a)

f ( 0 ) = lim f ( c n ) c n = 0

User profile picture
2022-01-27 00:00
Comments