Exercise 7.6.1

Recall that Thomae’s function

t ( x ) = { 1  if  x = 0 1 n  if  x = m n Q { 0 }  is in lowest terms with  n > 0 0  if  x Q

has a countable set of discontinuities occurring at precisely every rational number. Let’s prove that Thomae’s function is integrable on [ 0 , 1 ] with 0 1 t = 0 .

(a)
First argue that L ( t , P ) = 0 for any partition P of [ 0 , 1 ] .
(b)
Let 𝜖 > 0 , and consider the set of points D 𝜖 2 = { x [ 0 , 1 ] : t ( x ) 𝜖 2 } . How big is D 𝜖 2 ?
(c)
To complete the argument, explain how to construct a partition P 𝜖 of [ 0 , 1 ] so that U ( t , P 𝜖 ) < 𝜖 .

Answers

See Exercise 7.3.2

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2022-01-27 00:00
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