Exercise 1.4.11

Answers

To prove it’s sufficient we can use Theorem 1.5 and then we know W = span(W) is a subspace. To prove it’s necessary we can also use Theorem 1.5. Since W is a subspace contains W, we have span(W) W. On the other hand, it’s natural that span(W) W.

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2011-06-27 00:00
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