Exercise 1.4.2

Answers

1.
Original system {x1x22x3x4 = 3 x3 +2x4 = 4 4x3+8x4 = 16 . So we have solution is {(5 + s 3t,s,4 2t,t) : s,t 𝔽}.
2.
{(2,4,3)}.
3.
No solution.
4.
{(16 8s,9 + 3s,s,2) : s 𝔽}.
5.
{(4 + 10s 3t,3 3s + 2t,r,s,5) : s,t 𝔽}.
6.
{(3,4,2)}.
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2011-06-27 00:00
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