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Exercise 1.5.19

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We have $a_{1} A_{1}^{t} + a_{2} A_{2}^{t} + \dots + a_{k} A_{k}^{t} = 0$ implies $a_{1} A_{1} + a_{2} A_{2} + \dots + a_{k} A_{k} = 0$ . Then we have $a_{1} = a_{2} = \dots = a_{n} = 0$ .

jephianlin

2011-06-27 00:00

Exercise 1.5.19

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