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Exercise 1.5.20

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If ${f, g}$ is linearly dependent, then we have $f = kg$ . But this means $1 = f (0) = kg (0) = k \times 1$ and hence $k = 1$ . And $e^{r} = f (1) = kg (1) = e^{s}$ means $r = s$ .

jephianlin

2011-06-27 00:00

Exercise 1.5.20

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