Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 1.6.16
Exercise 1.6.16
Answers
We have for all . Hence the basis could be and the dimension is .
2011-06-27 00:00
Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 1.6.16
We have for all . Hence the basis could be and the dimension is .