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Exercise 1.6.7

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We have first ${u_{1}, u_{2}}$ is linearly independent. And since $u_{3} = - 4 u_{1}$ and $u_{4} = - 3 u_{1} + 7 u_{2}$ , we can check that ${u_{1}, u_{2}, u_{5}}$ is linearly independent and hence it’s a basis.

jephianlin

2011-06-27 00:00

Exercise 1.6.7

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