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Exercise 1.6.9

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If $a_{1} u_{1} + a_{2} u_{2} + a_{3} u_{3} + a_{4} u_{4} = (a_{1}, a_{1} + a_{2}, a_{1} + a_{2} + a_{3}, a_{1} + a_{2} + a_{3} + a_{4}) = 0$ we have $a_{1} = 0$ by comparing the first entry and then $a_{2} = a_{3} = a_{4} = 0$ . For the second question we can solve $(a_{1}, a_{2}, a_{3}, a_{4}) = a_{1} u_{1} + (a_{2} - a_{1}) u_{2} + (a_{3} - a_{2}) u_{3} + (a_{4} - a_{3}) u_{4}$ .

jephianlin

2011-06-27 00:00

Exercise 1.6.9

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