Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 2.1.11
This is the result of Theorem 2.6 since {(1,1),(2,3)} is a basis. And T(8,11) = T(2(1,1) + 3(2,3)) = 2T(1,1) + 3T(2,3) = (5,−3,16).
