Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 2.1.29
Exercise 2.1.29
Answers
For , we have since it’s a subspace and since it’s -invariant and finally .
2011-06-27 00:00
Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 2.1.29
For , we have since it’s a subspace and since it’s -invariant and finally .