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Exercise 2.1.30
Answers
Since for all , we have is -invariant. And that is due to Exercise 2.1.26(a).
2011-06-27 00:00
Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 2.1.30
Since for all , we have is -invariant. And that is due to Exercise 2.1.26(a).