Exercise 2.1.38

Answers

It’s additive since

T((x1 + iy1) + (x2 + iy2)) = (x1 + x2) i(y1 + y2) = T(x1 + iy1) + T(x2 + iy2).

But it’s not linear since T(i) = iiT(1) = 0.

User profile picture
2011-06-27 00:00
Comments