Exercise 2.4.12

Answers

We can check ϕβ is linear first. For x = i=1naivi and y = i=1nbivi, where

β = {v1,v2,,vn}

we have that

ϕβ(x+cy) = ( a1 + cb1 a2 + cb2 a n + cbn ) = ( a1 a2 a n )+c ( b1 b2 b n ) = ϕβ(x)+cϕβ(y).

And we can check whether it is injective and surjective. If ϕβ(x) = ( 0 0 0 )then this means x = i=1n0vi = 0. And for every ( a1 a2 a n ) + c in 𝔽n, we have that x = i=1naivi will be associated to it.

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2011-06-27 00:00
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