Exercise 2.6.4

Answers

We may returen the representation such that

(x,y,z) = (x−2y)(2 5,−3 10,−1 10)+(x+y+z)(3 5, 3 10, 1 10)+(y−3z)(1 5, 1 10,−3 10).

We may check that the set {(2 5,−3 10,−1 10),(3 5, 3 10, 1 10),(1 5, 1 10,−3 10)} is a basis and hence the desired set. By Theorem 2.24 {f1,f2,f3} is a basis for V ∗.

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2011-06-27 00:00
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