Exercise 2.7.10

Answers

Use induction on the number n of distinct scalar ci’s. When n = 1, the set {ec1t} is independent since ec1t is not identically zero. Suppose now the set {ec1t,ec2t,,ecnt} is independent for all n < k and for distinct ci’s. Assume that

i=1kb iecit = 0.

Since any differential operator is linear, we have

0 = (D ckI)( i=1kb ieckt) = i=1k1(c i ck)biecit.

This means that (ci ck)bi = 0 and so bi = 0 for all i < k by the fact that ci’s are all distinct. Finally bk is also zero since

bkeckt = 0.
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2011-06-27 00:00
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