Exercise 2.7.12

Let V be the solution space of an nth-order homogeneous linear differential equation with constant coefficients having auxiliary polynomial p(t). Prove that if p(t) = g(t)h(t), where g(t) and h(t) are polynomials of positive degree, then N(MD)) = R(g(Dv)) = p(D)(V ), where Dv : V V is defined by Dv(x) = x for x V . Hint: First prove g(D)(V ) N(i(D)). Then prove that the two spaces have the same finite dimension.

Answers

The second equality is the definition of range. To prove the first equality, we observe that R(g(DV )) N(h(D)) since

h(D)(g(D)(V )) = p(D)(V ) = {0}.

Next observe that

N(g(DV )) = N(g(D))

since N(g(D)) is a subspace in V . By Theorem 2.32, the dimension of N(g(DV )) = N(g(D)) is the degree of g. So the dimension of R(g(DV )) is the degree of h(t) minus the degree of g(t), that is the degree of h(t). So N(h(D)) and R(g(DV )) have the same dimension. Hence they are the same.

User profile picture
2011-06-27 00:00
Comments