Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 3.2.14
Exercise 3.2.14
Answers
- 1.
- For all we can express it as for some .
- 2.
- By Theorem 1.6.29(a) we have
- 3.
- We have that
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Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 3.2.14