Exercise 3.2.16

Answers

Since $P$ is invertible, we know that $L_{P}$ is an isomorphism. So by Exercise 2.4.17 we have that

rank (PA) = \dim (P (A (𝔽^{n})))

= \dim (A (𝔽^{n})) = A (𝔽^{n}) (A) .

jephianlin

2011-06-27 00:00