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Exercise 3.2.18

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Let $A_{i}$ be the matrix consists of the $i$ -th column of $A$ . Let $B_{i}$ be the matrix consists of the $i$ -th row of $B$ . It can be check that actually

AB = \sum_{i = 1}^{n} A_{i} B_{i}

and $A_{i} B_{i}$ has rank at most $1$ .

jephianlin

2011-06-27 00:00

Exercise 3.2.18

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