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Exercise 3.2.3

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It’s natural that rank $(A) = 0$ if $A = 0$ . For the converse, we know that if $A$ is not a zero matrix, we have $A_{ij} \neq 0$ and thus the $i$ -th row is an independent set. So rank $(A)$ can not be zero.

jephianlin

2011-06-27 00:00

Exercise 3.2.3

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