Exercise 3.2.7

Answers

We can do the Gaussian elimination and record what operation we’ve done.

( 121101 112 ) (1 2 1 0 2 0 1 1 2 )
(1 2 1 0 2 0 0 11 ) (1 2 1 0 1 0 0 11 )
(1 0 1 0 1 0 0 11 ) (101 0 1 0 001 )
(100 0 1 0 001 )

Let E1 = ( 1 00 1 1 0 0 01 ), E2 = ( 1 00 0 1 0 101 ), E3 = (1 0 0 01 20 0 0 1 ), E4 = (120 0 1 0 0 0 1 ), E5 = (100 0 1 0 011 ), E6 = (101 0 1 0 00 1 ).

Thus we have the matrix equals to E11E21E31E41E51E61.

User profile picture
2011-06-27 00:00
Comments