Exercise 3.2.8

Answers

It’s enough to show that $R (L_{A}) = R (L_{cA}$ . But this is easy since

R (L_{A}) = L_{A} (𝔽^{m}) = c L_{A} (𝔽^{m}) = L_{cA} (𝔽^{m}) = R (L_{c} A) .

jephianlin

2011-06-27 00:00