Exercise 3.3.13

Answers

In this model we should solve the equation $(I - A) x = d$ . And we can compute that $I - A$ is invertible and

{(I - A)}^{- 1} = (\begin{matrix} \frac{12}{5} & \frac{3}{5} \\ 1 & \frac{3}{2} \end{matrix}) .

So we know

x = {(I - A)}^{- 1} d = (\begin{matrix} \frac{39}{5} \\ \frac{19}{2} \end{matrix}) .

jephianlin

2011-06-27 00:00