Exercise 3.4.13

Answers

1.
Set v1 = (1,0,1,1,1,0) and v2 = (0,2,1,1,0,0). Check the two vectors satisfy the system of linear equation and so they are vectors in V . To show they are linearly independent, assume that
a(1,0,1,1,1,0) + b(0,2,1,1,0,0)
= (a,2b,a + b,a + b,a,0) = 0.

This means that a = b = 0 and the set is independent.

2.
Take the same basis β as that in the previous exercise and do Gaussian elimination.
(1011 1 3 0 2 1 1 2 2 111 0 0 0 1 1 0 1 0 0 100 0 1 0 0 0 0 0 0 1 )
(100 0 1 0 0 1 1 0 1 0 0011 0 0 0 0 0 0 0 1 000 0 0 0 0 0 0 0 0 0 )

So the set

{(1,0,1,1,1,0),(0,2,1,1,0,0),(1,1,1,0,0,0),(3,2,0,0,0,1)}

forms a basis for V .

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2011-06-27 00:00
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