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Linear Algebra

Exercise 3.4.1

Answers

1.: No. This form could only fit for row operation. For example, $x = 1$ and $x = 0$ has different solution set.
2.: Yes. This is Theorem 3.13.
3.: Yes. This is the result of Theorem 3.16.
4.: Yes. This is Theorem 3.14.
5.: No. For example, the system with corresponding augmented matrix $(\begin{matrix} 0 & 1 \end{matrix})$ has no solution.
6.: Yes. This is Theorem 3.15.
7.: Yes. This is Theorem 3.16.

jephianlin

2011-06-27 00:00

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