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Linear Algebra

Exercise 3.4.4

Answers

1.: The solution set is ${(\frac{4}{3}, \frac{1}{3}, 0, 0) + t (1, - 1, 1, 2)}$ . The basis is ${(1, - 1, 1, 2)}$ .
2.: The solution set is ${(1, 0, 1, 0) + s (- 1, 1, 0, 0) + t (1, 0, 1, 2)}$ . The basis is ${(- 1, 1, 0, 0), (1, 0, 1, 2)}$ .
3.: It has no solution.

jephianlin

2011-06-27 00:00

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