Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 4.3.20

Exercise 4.3.20

Answers

We can expand the matrix by the $n$ -th row and then by $(n - 1)$ -th row inductively. So we have that $\det (M) = \det (A)$ . Similarly, if we expand the matrix below by the first row and the second row inductively, we get the identity

\det (\begin{matrix} I & B \\ O & D \end{matrix}) = \det (D) .

jephianlin

2011-06-27 00:00

Exercise 4.3.20

Answers

Comments

Add answer