Exercise 4.5.7

Answers

It’s a $3$ linear function. We could write

δ (\begin{matrix} A_{11} & A_{12} & A_{13} \\ A_{21} & A_{22} & A_{23} \\ A_{31} & A_{32} & A_{33} \end{matrix}) = (A_{11}, A_{12}, A_{13}) \cdot (A_{21} A_{32}, 0, 0)

= (A_{21}, A_{22}, A_{23}) \cdot (A_{11} A_{32}, 0, 0) = (A_{31}, A_{32}, A_{33}) \cdot (0, A_{11} A_{21}, 0)

and get the result.

jephianlin

2011-06-27 00:00