Exercise 4.5.8

Answers

It’s not a $3$ -linear function. We have that

δ (\begin{matrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 1 & 1 & 0 \end{matrix}) = 1 \neq = 2 δ (\begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 1 & 0 \end{matrix}) = 2 .

jephianlin

2011-06-27 00:00