Exercise 5.1.10

Answers

1.
What did the author want to ask? Just calculate it!
2.
Just calculate it and get the answer (λ t)n, where n is the dimension of V .
3.
We already have that for any ordered basis β, [λIV ]β = λI, a diagonal matrix. So it’s diagonalizable. By the previous exercise, we also have that the only eigenvalue is the zero of the characteristic polynomial, λ.
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2011-06-27 00:00
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