Exercise 5.1.17

Answers

1.
If T(A) = At = λA for some λ and some nonzero matrix A, say Aij0, we have
Aij = λAji

and

Aji = λAij

and so

Aij = λ2A ij.

This means that λ can only be 1 or 1. And these two values are eigenvalues due to the existence of symmetric matrices and skew-symmetric matrices.

2.
The set of nonzero symmetric matrices are the eigenvectors corresponding to eigenvalue 1, while the set of nonzero skew-symmetric matrices are the eigenvectors corresponding to eigenvalue 1.
3.
It could be { (10 0 1 ), (01 0 0 ), (00 1 0 ), (1 0 0 1 )}.
4.
Let Eij be the matrix with its ij-entry 1 and all other entries 0. Then the basis could be
{Eii}i=1,2,,n {Eij + Eji}i>j {Eij Eji}i>j.
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2011-06-27 00:00
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