Exercise 5.3.11

Answers

The matrix would be

A = (\begin{matrix} 0.7 & 0.2 & 0 \\ 0.1 & 0.6 & 0.2 \\ 0.2 & 0.2 & 0.8 \end{matrix}) .

So the vector in 1950 would be

A (\begin{matrix} 0.1 \\ 0.5 \\ 0.4 \end{matrix}) = (\begin{matrix} 0.197 \\ 0.339 \\ 0.464 \end{matrix}) .

Since it’s regular, we may just find the fixed vector

(\begin{matrix} 0.2 \\ 0.3 \\ 0.5 \end{matrix}) .

jephianlin

2011-06-27 00:00